Solid State Physics- Finding concentration of donor atoms (Nd)

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SUMMARY

The discussion focuses on calculating the concentration of donor atoms (Nd) required to form an n-type compensated semiconductor in silicon at 300K, where the acceptor atom concentration (Na) is 5 x 1015 cm-3 and the Fermi level is 0.215 eV below the conduction band edge. The relevant equation used is (ni2) = (Nd - 5 x 1015) * p0, where ni represents the intrinsic carrier concentration and p0 denotes the hole concentration. The challenge lies in determining the value of Nd to achieve the desired semiconductor properties.

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  • Understanding of semiconductor physics
  • Familiarity with intrinsic carrier concentration (ni) in silicon
  • Knowledge of Fermi level positioning in n-type and p-type semiconductors
  • Ability to manipulate equations involving carrier concentrations
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  • Research the intrinsic carrier concentration (ni) of silicon at 300K
  • Learn about the relationship between Fermi level and carrier concentrations in semiconductors
  • Study the concept of compensated semiconductors and their properties
  • Explore methods for calculating hole concentration (p0) in n-type materials
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Homework Statement



Silicon at T= 300K contains acceptor atoms at a concentration of Na = 5*10^15 cm-3. Donor atoms are added forming an n-type compensated semiconductor such that the fermi level is 0.215 eV below the conduction band edge. What concentration of donor atoms are added?


Homework Equations


I have one equation byt i still have one unknown:





The Attempt at a Solution



here is what i have:
(ni^2) = (Nd- 5*10^15) * po
 
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where ni is the intrinsic carrier concentration and po is the hole concentration. Nd is the donor atoms added, but I don't know what this is. I'm not sure how to proceed. Any help would be much appreciated. Thank you!
 

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