Solution for Expressing Derivatives in Terms of u

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cos[tex]\theta[/tex] = 1 when [tex]\theta[/tex] = 0

so that gives r = x, the initial condition?
 
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gtfitzpatrick said:
cos[tex]\theta[/tex] = 1 when [tex]\theta[/tex] = 0

so that gives r = x, the initial condition?

The initial condition was [tex]u(x,0)=0[/tex], which we found was equivalent to [tex]w(r,\theta)=0[/tex]. The fact that [tex]r=x[/tex] when [tex]y=0[/tex] doesn't restrict the solution.
 
provided 0<r<[tex]\infty[/tex] ?
 
gtfitzpatrick said:
provided 0<r<[tex]\infty[/tex] ?

Yes, the initial condition doesn't pick out a value of r, though it does exclude [tex]r=0[/tex] for a reason that will probably become apparent when you have the complete solution in hand.
 
cool thank a mill