solve a limit with the form (x^n)(e^ax) when x approaches to infinity??? Well, my question is how to solve a limit with the form (x^n)(e^ax) when x approaches to infinity using L´Hopital rule?? I made a try, transforming the limit to (x^n)/(e^-ax), and using L´Hopital repeatedly, gives me something like this: (nx^n-1/(-ae^ax), (n(n-1)x^n-2/(a^2e^-ax).... So, the question, if this is correct (although i don't think so), is how i can simplify this?? If i´m wrong (which is more probably), please don't be so hard with me, hehe :) Thanks for the answers!!