Solve a limit with the form (x^n)(e^ax) when x approaches to infinity?

  • Thread starter Wilfired
  • Start date
  • #1
2
0

Main Question or Discussion Point

solve a limit with the form (x^n)(e^ax) when x approaches to infinity???

Well, my question is how to solve a limit with the form (x^n)(e^ax) when x approaches to infinity using L´Hopital rule??
I made a try, transforming the limit to (x^n)/(e^-ax), and using L´Hopital repeatedly, gives me something like this:
(nx^n-1/(-ae^ax), (n(n-1)x^n-2/(a^2e^-ax)....
So, the question, if this is correct (although i don't think so), is how i can simplify this??
If i´m wrong (which is more probably), please don't be so hard with me, hehe :)
Thanks for the answers!!
 

Answers and Replies

  • #2
lurflurf
Homework Helper
2,432
132


You do not need L´Hopital rule. Show (x^n)(e^ax) and (e^ax) have the same limit.
 
  • #3
haruspex
Science Advisor
Homework Helper
Insights Author
Gold Member
33,585
5,471


Is it known that n and a are > 0?
 
  • #4
2
0

Related Threads on Solve a limit with the form (x^n)(e^ax) when x approaches to infinity?

  • Last Post
Replies
9
Views
10K
Replies
3
Views
2K
  • Last Post
Replies
8
Views
3K
Replies
2
Views
5K
Replies
2
Views
2K
  • Last Post
Replies
6
Views
43K
Replies
7
Views
3K
Replies
6
Views
2K
Replies
2
Views
4K
Top