(adsbygoogle = window.adsbygoogle || []).push({}); solve a limit with the form (x^n)(e^ax) when x approaches to infinity???

Well, my question is how to solve a limit with the form (x^n)(e^ax) when x approaches to infinity using L´Hopital rule??

I made a try, transforming the limit to (x^n)/(e^-ax), and using L´Hopital repeatedly, gives me something like this:

(nx^n-1/(-ae^ax), (n(n-1)x^n-2/(a^2e^-ax)....

So, the question, if this is correct (although i don't think so), is how i can simplify this??

If i´m wrong (which is more probably), please don't be so hard with me, hehe :)

Thanks for the answers!!

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# Solve a limit with the form (x^n)(e^ax) when x approaches to infinity?

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