Solve (ab)^2 + ab - a^2 - 4b^2 = 0

  • Thread starter Thread starter soopo
  • Start date Start date
Join the discussion
Registration is free. Ask a follow-up in this thread, or start your own.
3 replies · 2K views
soopo
Messages
222
Reaction score
0

Homework Statement



Solve the following equation for `a`.
(ab)^2 + ab - a^2 - 4b^2 = 0


The Attempt at a Solution



ab( ab + 1 ) - a^2 -4b^2 =

I perhaps should now use some sort of Diophantine equation.
However, I am not sure.
 
Physics news on Phys.org
Just treat it as a quadratic equation in 'a', regarding 'b' as a constant.
 
hiya,

treat b like a constant.
maybe the best way to solve this for a is to put the equation in the form of a quadratic, like:
ax^2+bx+c=0
(in this case you will have a instead of x) then use the quadratic formula to find the value(s) for a.
 
Dick said:
Just treat it as a quadratic equation in 'a', regarding 'b' as a constant.

sara_87 said:
hiya,

treat b like a constant.
maybe the best way to solve this for a is to put the equation in the form of a quadratic, like:
ax^2+bx+c=0
(in this case you will have a instead of x) then use the quadratic formula to find the value(s) for a.
Two great minds with a single thought!