Solve Bragg Diffraction: n(λ)/2sinθ

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    Bragg Diffraction
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SUMMARY

The discussion centers on solving Bragg diffraction using the formula 2dsin(θ) = n(λ). The user correctly identifies that to find d, the equation rearranges to d = n(λ)/(2sin(θ)). The angle θ corresponds to the peak value from the graph, with the first peak representing n = 1 and the second peak potentially representing n = 2, although this is not mandatory. The user successfully resolves their confusion regarding the angle and the order of the diffraction peaks.

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  • Understanding of Bragg's Law in crystallography
  • Familiarity with the concepts of diffraction and interference
  • Basic knowledge of microwave physics
  • Ability to interpret graphical data related to peak values
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  • Learn about the significance of diffraction orders in wave phenomena
  • Explore the relationship between wavelength and diffraction patterns
  • Investigate experimental setups for measuring diffraction angles
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oldspice1212
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Bragg diffraction of microwaves lab.
Hey guys I have a quick question so for bragg diffraction the formula is 2dsin(theta) = n(lambda).
So I have to solve for d, which is d = n(lambda)/(2sin(theta)), but here is the problem: I'm not entirely sure what theta is, as I'm using a graph with 2 peak values, so would theta be just the peak value, and the first peak is n = 1, and peak 2 is n = 2?

Thanks
 
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Thanks for the post! Sorry you aren't generating responses at the moment. Do you have any further information, come to any new conclusions or is it possible to reword the post?
 
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Hey no problem, thanks for checking that means a lot to me.
I figured it out eventually, thank you very much though!
 
Yes, the angle in the formula will be the peak value.
Regarding the order of the diffraction peak, it is possible that the second peak is the second order of the first. But it is not necessary.
What was your sample?
 

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