Solve Bragg Diffraction: n(λ)/2sinθ

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    Bragg Diffraction
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Homework Help Overview

The discussion revolves around Bragg diffraction in the context of a lab experiment involving microwaves. The original poster seeks clarification on the application of the Bragg's law formula and the interpretation of the angle theta in relation to observed peak values on a graph.

Discussion Character

  • Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • The original poster attempts to understand how to determine the angle theta from a graph with multiple peak values and questions whether theta corresponds to the peak values themselves. Other participants provide insights on the relationship between the peaks and their order.

Discussion Status

The discussion includes attempts to clarify the definition of theta and the order of diffraction peaks. Some participants offer guidance on interpreting the peaks, while the original poster indicates they have resolved their confusion.

Contextual Notes

The original poster mentions using a graph with two peak values, which raises questions about the interpretation of these values in the context of Bragg's law. There is an implication of uncertainty regarding the sample used in the experiment.

oldspice1212
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Bragg diffraction of microwaves lab.
Hey guys I have a quick question so for bragg diffraction the formula is 2dsin(theta) = n(lambda).
So I have to solve for d, which is d = n(lambda)/(2sin(theta)), but here is the problem: I'm not entirely sure what theta is, as I'm using a graph with 2 peak values, so would theta be just the peak value, and the first peak is n = 1, and peak 2 is n = 2?

Thanks
 
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Thanks for the post! Sorry you aren't generating responses at the moment. Do you have any further information, come to any new conclusions or is it possible to reword the post?
 
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Hey no problem, thanks for checking that means a lot to me.
I figured it out eventually, thank you very much though!
 
Yes, the angle in the formula will be the peak value.
Regarding the order of the diffraction peak, it is possible that the second peak is the second order of the first. But it is not necessary.
What was your sample?
 

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