Solve Car Crash Problem: 1082667 J Force Applied

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SUMMARY

The discussion centers on calculating the force applied to a 1015 kg automobile that comes to a stop after hitting a tree at 32 m/s over a duration of 0.03 seconds. The correct formula to determine the force is F = m * (Δv/Δt), which results in a force of 1082667 N. Participants clarify the relationship between mass, acceleration, and force, emphasizing the importance of understanding the equation for solving similar physics problems.

PREREQUISITES
  • Understanding of Newton's Second Law of Motion (F = ma)
  • Knowledge of kinematic equations, specifically Δv = v_final - v_initial
  • Basic algebra for manipulating equations
  • Familiarity with units of force (Newtons)
NEXT STEPS
  • Study the derivation and applications of Newton's Second Law of Motion
  • Learn about kinematic equations in physics
  • Explore real-world applications of force calculations in automotive safety
  • Investigate the concept of impulse and momentum in collision scenarios
USEFUL FOR

Students studying physics, particularly those focusing on mechanics, as well as educators looking for practical examples of force calculations in real-world scenarios.

sweedeljoseph

Homework Statement


A 1015 kg automobile hits a tree at 32 m/s, coming to a complete stop in 0.03 s. What force was applied to the car by the tree? (Take the forward direction of the car as positive).

Homework Equations


i don't know what would be relevant.
f=m/a
f (cos theta) d

The Attempt at a Solution


the answer from the teacher is 1082667 J but i don't know how youre supposed to find that. i think I am missing some equation. i looked through everything can't really find one that has to do with mass velocity and time for a force. and i have no idea how to make up equations. well i probably could but it wouldn't be right.

thank you!
sweedeljoseph
 
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No...the formula is

F =ma =F \frac{ \Delta v}{\Delta t} = 1015 \left( \frac{32-0}{0.03} \right)

get it?
 
oh yeah i meant that
haha

but how would you use that in the problem? because the mass is given. don't you use that? well you must have to because the answer is 1082667 J and i have no idea how to get that.
 
sweedeljoseph said:
oh yeah i meant that
haha

but how would you use that in the problem? because the mass is given. don't you use that? well you must have to because the answer is 1082667 J and i have no idea how to get that.

Sorry, there should have been a m, let me try it agian:

F =ma =m \frac{ \Delta v}{\Delta t} = 1015 \left( \frac{32-0}{0.03} \right)

Do you get it now?
 
yes thank you so much!
i never learned that equation until now. i knew a=delta v/ delta t but that's it. i didnt know it was force.

thanks again
sweedeljoseph
 
sweedeljoseph said:
yes thank you so much!
i never learned that equation until now. i knew a=delta v/ delta t but that's it. i didnt know it was force.
That's because it isn't force only multiplied with a mass it becomes a force.
 
yeah i definitely feel stupid but now i get it!
 

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