Solve Cheese Problem Homework: Find θ1 & θ2

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SUMMARY

The discussion centers on solving for the angles θ1 and θ2 in a physics problem involving a 4.50 kg block of gruyere cheese suspended by two ropes with tensions of 28.3 N and 40.5 N. The equations of equilibrium are established as T1cos(θ1) + T2cos(θ2) = 0 for the x-axis and T1sin(θ1) + T2sin(θ2) = mg for the y-axis. Participants suggest using trigonometric identities to eliminate one variable and solve for the angles, specifically using arccos and arcsin functions to express θ2 in terms of θ1.

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Homework Statement



A 4.50 kg block of gruyere cheese is suspended as shown. Rope 1 on the left has a tension of 28.3 N; rope 2 on the right has a tension of 40.5 N. (a) What is θ1, the angle made by rope 1? (b) What is θ2? State each angle as the positive angle "inside" the triangle the ropes form.

Homework Equations



F=ma
It is suggested we use these: http://i47.tinypic.com/mtxv1z.png


The Attempt at a Solution



I've got the x-axis as T1cosθ1+T2cosθ2=0
and the y-axis as T1sinθ1+T2sinθ2=mg

And now I'm stuck...Please help!
 
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You are given T1 and T2, right? So you have two equations, which you can use to eliminate θ2 and solve for θ1. For this you will probably need the given identities (for example, you will get θ2 = arccos(... θ1 ...)
 
Okay, so if I use T1cosθ1+T2cosθ2=0 and plug in the values for T1 and T2 and solve for θ1 I get arccos(1.43cosθ2) and I'm lost again.

Do I set this equal as in: arccos(1.43cosθ2)=arcsin(sqrt((1-arccos(1.43cosθ2))^2)))

and then solve?
 

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