Solve Collision Momentum: Find Speed of Pucks A & B

[neoncrazy101]

Homework Statement

The drawing shows a collision between two pucks on an air-hockey table. Puck A has a mass of 0.0180 kg and is moving along the x-axis with a velocity of +7.71 m/s. It makes a collision with puck B, which has a mass of 0.0360 kg and is initially at rest. The collision is not head-on. After the collision, the two pucks fly apart with the angles shown in the drawing. Find the speed of (a) puck A and (b) puck B.
http://edugen.wileyplus.com/edugen/courses/crs2216/art/qb/qu/c07/ch07p_30.gif

Homework Equations

m₁v_f1x+m₂v_f2x = m₁v_o1+m₂v_o2

0 = M_f1V₁sin(65) - M₂V_f2sin(37)

M₁ = .0180
M₂ = .0360
V_o1 = 7.71
V_o0 = 0

The Attempt at a Solution

.018(v)+.036(v) = .018(7.71)
.054v = .13878
v = 2.57. (Terribly wrong)

.018(V_f1)sin(65) - .036(V_f2)sin(37)

My problem is I'm getting so confused as to what I am solving for. I mean, I know I'm solving for the final speeds of puck A and puck B but I'm confused as to how to get there. I'm just plan lost.

 

[tiny-tim]

hi neoncrazy101!

.018(v)+.036(v) = .018(7.71)
.054v = .13878
v = 2.57. (Terribly wrong)

but your two vs are different

also, momentum is conserved in both the x direction and the y direction, so you need an equation for each