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Hemingway
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Hello - I am pretty sure this is correct but there is no answer for me to check. My friend (who is a lot smarter than me :P ) got a different answer entirely. Is the following answers correct?
Puck A has a mass of 0.0300 kg and is moving along the x-axis with a velocity of +4.20 m/s. It makes a collision with puck B, which has a mass of 0.0600 kg and is initially at rest. The collision is not head-on. After the collision, the two pucks fly apart with the angles shown in the drawing. Find the speed of (a) puck A and (b) puck B.
puck a is 65 degrees above x axis
puck b is 37 degrees below the x axis
(0.0300) (4.2) + 0 = (0.0300) (VA COS 65) + .0600 (VB COS 37)
0.126 = 0.0127 VA + 0.0479VB
0 = 0.0300 (VA SIN 65) + (0.0600)(-VBSIN 37)
= 0.0272 VA + -0.0361 VB
0.0361VB = 0.0272VA
VB = 0.0272VA/0.0361
VB = 0.753 VA
0.126 = 0.0127 VA + 0.0479VB
0.126 = 0.0127 VA + (0.0479)(0.753)
0.126 = 0.0127 VA + 0.0361 VA
0.126 = 0.0488 VA
VA = 0.126/10.0488
VA = 2.58 m/s
VB = 2.58 m/s x 0.753
= 1.94m/s
Homework Statement
Puck A has a mass of 0.0300 kg and is moving along the x-axis with a velocity of +4.20 m/s. It makes a collision with puck B, which has a mass of 0.0600 kg and is initially at rest. The collision is not head-on. After the collision, the two pucks fly apart with the angles shown in the drawing. Find the speed of (a) puck A and (b) puck B.
puck a is 65 degrees above x axis
puck b is 37 degrees below the x axis
The Attempt at a Solution
(0.0300) (4.2) + 0 = (0.0300) (VA COS 65) + .0600 (VB COS 37)
0.126 = 0.0127 VA + 0.0479VB
0 = 0.0300 (VA SIN 65) + (0.0600)(-VBSIN 37)
= 0.0272 VA + -0.0361 VB
0.0361VB = 0.0272VA
VB = 0.0272VA/0.0361
VB = 0.753 VA
0.126 = 0.0127 VA + 0.0479VB
0.126 = 0.0127 VA + (0.0479)(0.753)
0.126 = 0.0127 VA + 0.0361 VA
0.126 = 0.0488 VA
VA = 0.126/10.0488
VA = 2.58 m/s
VB = 2.58 m/s x 0.753
= 1.94m/s
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