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Hello - I am pretty sure this is correct but there is no answer for me to check. My friend (who is a lot smarter than me :P ) got a different answer entirely. Is the following answers correct?

Puck A has a mass of 0.0300 kg and is moving along the x axis with a velocity of +4.20 m/s. It makes a collision with puck B, which has a mass of 0.0600 kg and is initially at rest. The collision is not head-on. After the collision, the two pucks fly apart with the angles shown in the drawing. Find the speed of (a) puck A and (b) puck B.

puck a is 65 degrees above x axis

puck b is 37 degrees below the x axis

(0.0300) (4.2) + 0 = (0.0300) (V

0 = 0.0300 (V

= 0.0272 V

0.0361V

V

0.126 = 0.0127 VA + 0.0479VB

0.126 = 0.0127 VA + (0.0479)(0.753)

0.126 = 0.0127 VA + 0.0361 VA

0.126 = 0.0488 VA

VA = 0.126/10.0488

VA = 2.58 m/s

VB = 2.58 m/s x 0.753

= 1.94m/s

## Homework Statement

Puck A has a mass of 0.0300 kg and is moving along the x axis with a velocity of +4.20 m/s. It makes a collision with puck B, which has a mass of 0.0600 kg and is initially at rest. The collision is not head-on. After the collision, the two pucks fly apart with the angles shown in the drawing. Find the speed of (a) puck A and (b) puck B.

puck a is 65 degrees above x axis

puck b is 37 degrees below the x axis

## The Attempt at a Solution

(0.0300) (4.2) + 0 = (0.0300) (V

_{A}COS 65) + .0600 (V_{B}COS 37)__0.126 = 0.0127 V___{A}+ 0.0479V_{B}0 = 0.0300 (V

_{A}SIN 65) + (0.0600)(-V_{B}SIN 37)= 0.0272 V

_{A}+ -0.0361 V_{B}0.0361V

_{B}= 0.0272V_{A}V

_{B}= 0.0272VA/0.0361__VB = 0.753 VA__0.126 = 0.0127 VA + 0.0479VB

0.126 = 0.0127 VA + (0.0479)(0.753)

0.126 = 0.0127 VA + 0.0361 VA

0.126 = 0.0488 VA

VA = 0.126/10.0488

VA = 2.58 m/s

VB = 2.58 m/s x 0.753

= 1.94m/s

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