More generally, if you have n numbers, given as an array, num, and want to calculate their average it is
N= 0
for (i= 0; i< n; i++)
N= N+ num
Average= N/n;
In the case that n= 3, N would start at 0, after the i= 0 loop, N= 0+ num[0]= num[0], after the i= 1 loop, N= num[0]+ num[1], and after the i= 2 loop, N= (num[0]+ num[1])= num[2]= num[0]+ num[1]+ num[2]. The loop stops there because i= 3 does not satify "i< 3", and then Average= (num[0]+ num[1]+ num[2])/3.