Solve Currents in I3, I2, and I1

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SUMMARY

The discussion focuses on solving for the currents I1, I2, and I3 in a circuit using Kirchhoff's loop rule. Three loop equations are established: Loop 1, Loop 2, and Loop 3, with specific voltage and current values provided. It is noted that the third equation is redundant as it is a linear combination of the first two equations. The user is advised to apply the junction rule to complement their analysis.

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  • Understanding of Kirchhoff's loop rule
  • Familiarity with Kirchhoff's junction rule
  • Basic circuit analysis techniques
  • Ability to solve linear equations
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  • Review Kirchhoff's laws in detail
  • Practice solving circuit problems using both loop and junction rules
  • Learn to identify independent equations in circuit analysis
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Homework Statement



find the current in I3 and I2 and I1

Homework Equations


junction Rule


The Attempt at a Solution


Loop 1 : -I1(4.1) + 29V - I1 (3.3) -I3(2.9)
-I1(7.4) -I3(2.9) = -29V

Loop 2 : I3 (2.9) - I2 (5.5) +16 V - I2(2)
-I2(7.5) + I3(2.9) = -16 V

Loop 3 : -I1(4.1) + 29V - I1(3-3)-I2(5.5) +16V-I2(2)
-I1(7.4)-I2(7.5)=-45V

Please help ASAP thanks!
 

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itryphysics said:

Homework Statement



find the current in I3 and I2 and I1

Homework Equations


junction Rule


The Attempt at a Solution


Loop 1 : -I1(4.1) + 29V - I1 (3.3) -I3(2.9)
-I1(7.4) -I3(2.9) = -29V

Loop 2 : I3 (2.9) - I2 (5.5) +16 V - I2(2)
-I2(7.5) + I3(2.9) = -16 V

Loop 3 : -I1(4.1) + 29V - I1(3-3)-I2(5.5) +16V-I2(2)
-I1(7.4)-I2(7.5)=-45V

Please help ASAP thanks!

Hi itryphysics! :smile:

(The third equation gives you no extra information …

it's just the sum of the first two equations …

the number of independent loop equations is the same as the number of independent loops. :wink:)

You've headed this "junction rule", but you haven't used the junction rule, only the loop rule.
 

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