Sorry for the quality of the image. This is the best I can come up with with my cellphone.
What is the current through the 10 ohms resistor?
Is the current from left to right or right to left?
Kirchhoff's loop law
Kirchhoff's junction law
The Attempt at a Solution
1) I1 = I2 + I3 ==> I3 = I1 -I2
2) -5(I1) + 12V - 10(I2) + 3V = 0
15V = 10(I2) + 5(I1)
I1 = (15V - 10(I2))/5
3) -5(I3) + 9V + 3V + 10(I2) = 0
-5(I1-I2) + 12V + 10 (I2) = 0
12V = -15 (I2) + 5 (I1)
= -15 (I2) + 15V - 10 (I2)
-3V = -25 (I2) ===> I2 = 0.12 A, from right to left.
This answer is incorrect. The correct answer is 0.36 A. Can someone please give me a hint as to what I'm doing wrong ?