Solve DE Using Substitution and Integration Techniques | Helpful Tips Included

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SUMMARY

The discussion focuses on solving the differential equation (DE) \(\frac{dy}{dx}=\frac{y+\sqrt{x^{2}+y^{2}}}{x}\) using the substitution \(y=xu\). This substitution simplifies the DE to the form \(x\frac{du}{dx}=\sqrt{u^{2}+1}\). The particular solution for the curve passing through the point (1,0) is derived as \(y=\frac{1}{2}(x^{2}-1)\). The integration technique involving inverse hyperbolic functions is highlighted as a necessary method for solving the DE.

PREREQUISITES
  • Understanding of differential equations, specifically separable and inseparable types.
  • Familiarity with substitution methods in solving DEs.
  • Basic knowledge of integration techniques, including inverse hyperbolic functions.
  • Experience with using computational tools like Wolfram Alpha for solving mathematical problems.
NEXT STEPS
  • Learn about inverse hyperbolic functions and their applications in integration.
  • Study the method of substitution in differential equations in more depth.
  • Explore the integration of secant functions and related trigonometric identities.
  • Practice solving various forms of differential equations, including those requiring integrating factors.
USEFUL FOR

High school students, mathematics educators, and anyone interested in mastering techniques for solving differential equations, particularly through substitution and integration methods.

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The problem states:

"By using the substitution [itex]y=xu[/itex], show that the differential equation [itex]\frac{dy}{dx}=\frac{y+\sqrt{x^{2}+y^{2}}}{x}, x>0[/itex] can be reduced to the d.e. [itex]x\frac{du}{dx}=\sqrt{u^{2}+1}[/itex].

Hence, show that if the curve passes through the point [itex](1,0)[/itex], the particular solution is given by [itex]y=\frac{1}{2}(x^{2}-1)[/itex]."

I managed to get the d.e. into the form [itex]x\frac{du}{dx}=\sqrt{u^{2}+1}[/itex] but I have no idea how to integrate [itex]\frac{du}{\sqrt{u^{2}+1}}[/itex]. Wolfram Alpha is giving me some inverse hyperbolic sine stuff which I haven't learned yet (I'm in high school). All I've really 'learned' from my teacher so far was solving separable DE's, and inseparable DE's with [itex]y=ux[/itex], however some of the questions that we were given required other techniques like integrating factors and stuff. Is this DE a special case or something?

Anyways, how would I approach this? Do I square both sides to get rid of the square root sign?

Many thanks.
 
Last edited:
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Try the substitution u=tan v.
 
I got it! Thank you. I didn't know how to integrate secx but Wolfram helped out.
 

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