Solve Differential eq with initial conditions

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Homework Help Overview

The problem involves solving a differential equation of the form ∂H/∂t = -4κH² with an initial condition H(0) = 1/L². The goal is to find the function H(t).

Discussion Character

  • Exploratory, Mathematical reasoning, Problem interpretation

Approaches and Questions Raised

  • The original poster attempts a solution using Taylor series expansion but finds it leads to an incorrect result. Another participant suggests separating variables as an alternative approach. There is a discussion about the validity of the Taylor series method and its equivalence to the separation of variables approach to first order.

Discussion Status

Participants are exploring different methods to solve the differential equation. Some guidance has been provided through hints, and there is an acknowledgment of the effectiveness of the separation of variables method. The discussion reflects a mix of interpretations and approaches without reaching a consensus.

Contextual Notes

The original poster expresses confusion regarding their initial approach and seeks clarification on its validity. There is an emphasis on the initial conditions and the nature of the differential equation being discussed.

billiards
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Homework Statement



Solve: [tex]\frac{\partial H}{\partial t} = -4\kappa H^{2}[/tex]

With initial condition: [tex]H(0) = 1/L^{2}[/tex]

To find: [tex]H(t) = \frac{1}{4\kappa t + L^{2}}[/tex]

2. The attempt at a solution

I tried using Taylor series expansion such that:

[tex]H(t)\approx H(0)+t\frac{\partial H}{\partial t}(0)+...[/tex]

To first order this yielded: [tex]H(t)=\frac{L^{2}-4\kappa t}{L^{4}}[/tex]

This is wrong unless t and/or k equals zero. Therefore this is wrong, it is not the general solution. Please help if you can. Thanks.
 
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hi billiards! :smile:
billiards said:
I tried using Taylor series expansion …

eugh!

just separate the variables: dH/H2 = -4k dt :wink:
 
tiny-tim said:
separate the variables

Thanks tiny-tim, with that hint I solved it straight away. You have no idea how long I was stuck.

Out of interest, what was wrong with my Taylor series approach?
 
billiards said:
Thanks tiny-tim, with that hint I solved it straight away. You have no idea how long I was stuck.

he he :biggrin:
Out of interest, what was wrong with my Taylor series approach?

nothing … they are the same to first order …

what is the inverse of 1 + (4k/L2)t, to first order ? :wink:
 

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