Solve Direction of Impulse: Linear Momentum & Force

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SUMMARY

The discussion focuses on understanding the direction of impulse and force in the context of linear momentum. A 0.5kg ball strikes the ground and rebounds, prompting the calculation of the impulse exerted by the ground on the ball in the x direction. The correct interpretation is that the impulse is negative, indicating that the force exerted by the ground acts opposite to the initial positive direction of the ball's momentum. The key takeaway is that while the impulse magnitude is important, its direction reflects the change in momentum.

PREREQUISITES
  • Understanding of linear momentum principles
  • Familiarity with impulse-momentum theorem
  • Basic knowledge of vector direction in physics
  • Ability to perform calculations involving force and impulse
NEXT STEPS
  • Study the impulse-momentum theorem in detail
  • Learn how to visualize forces and impulses using free-body diagrams
  • Explore examples of impulse in different collision scenarios
  • Review the concept of negative impulse and its implications in momentum changes
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Students studying physics, particularly those focusing on mechanics, as well as educators looking to clarify concepts of impulse and momentum in practical scenarios.

jtmbii
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This should be a quick question. I'm not understanding the overall concept of impulse/force direction very well. I appreciate your help.

Homework Statement


The 0.5kg ball strikes the rough ground and rebounds wit the velocities as shown. Determine the magnitude of the impulse the grounds exerts on the ball in the x direction. Assume that the ball does not slip when it strikes the ground, ,and neglect the size of the ball and the impulse produced by the weight of the ball.

Homework Equations


Principle of Linear Impulse and Momentum:
gif.latex?mv_1%20-%20%5Csum%20%5Cint_%7Bt_1%7D%5E%7Bt_2%7DF_x%20dt%20%3D%20mv_2.gif


The Attempt at a Solution


I started off with the following
25cos45%29%20+%20%5Csum%20%5Cint_%7Bt_1%7D%5E%7Bt_2%7DF%20dt%20%3D%20%280.5%29%2810cos30%29.gif

then got F = -4.509 N
I then realized that impulse should be in the negative direction(?) Thus, to get a positive value of force like the answer in the book, the equation should be:
29%2825cos45%29%20-%20%5Csum%20%5Cint_%7Bt_1%7D%5E%7Bt_2%7DF%20dt%20%3D%20%280.5%29%2810cos30%29.gif

Is this correct? But I cannot understand why. Time is scalar so impulse direction should depend on the direction of the force (?) Though how am I supposed to tell this direction? To me, it looks like the force is positive in the x direction before it hits the ground, and after. This is why I am confused. I want to understand this more visually. Thank you.
 

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jtmbii said:
Is this correct? But I cannot understand why. Time is scalar so impulse direction should depend on the direction of the force (?) Though how am I supposed to tell this direction? To me, it looks like the force is positive in the x direction before it hits the ground, and after. This is why I am confused. I want to understand this more visually. Thank you.
You were right the first time. The impulse is negative (the momentum decreases), meaning the force is opposite to the direction you took as positive. No big deal. All you care about is the magnitude anyway.
 
Doc Al said:
You were right the first time. The impulse is negative (the momentum decreases), meaning the force is opposite to the direction you took as positive. No big deal. All you care about is the magnitude anyway.
Momentum decreases. I see. Thank you so much for this.
 

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