Solve EM Waves Problem: Time Difference of Important News Transmission

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SUMMARY

The discussion focuses on calculating the time difference in receiving a news announcement transmitted via radio waves and sound waves. The speed of radio waves is established as 3 x 108 m/s, while the speed of sound in air is 343 m/s. The distances involved are 81 km for radio waves and 2.3 m for sound waves. The correct approach involves using the formula time = distance/speed for both mediums to find the time difference accurately.

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  • Knowledge of sound wave transmission in air
  • Familiarity with basic physics equations related to speed, distance, and time
  • Ability to convert units (e.g., kilometers to meters)
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Homework Statement


An important news announcement is transmitted by radio waves to people who are 81 km away, sitting next to their radios, and by sound waves to people sitting across the newsroom, 2.3 m from the newscaster. Take the speed of sound in air to be 343 m/s. What is the difference in time that the message is recieved?


Homework Equations


c = f*lamda


The Attempt at a Solution


c1 = 3*10^8 m/s
lamda1 = 81km
c2 = 343 m/s
lamda2 = 2.3m

f1 = c1/lamda1
f2 = c2/lamda2

T = 1/(f1-f2) = time difference

What am I doing wrong? Thanks in advance for any help!
 
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I think this is more of a distance problem than a waves problem.

So, the speed of radio waves is the speed of light, 3*10^8 m/s...so use time=distance/speed
Do the same thing for sound, where it travels at 343 m/s.
 
awesome...thanks!
 

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