Solve Energy Dissipation in Resistor: I = 0.09 A, R = 80.0 Ω

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SUMMARY

The total energy dissipated as heat in a resistor with a resistance of 80.0 Ω and a current of 0.09 A over a duration of 1 minute is calculated using the formula for electric power, P = I²R. The power dissipated is 0.648 W, leading to a total energy dissipation of 38.88 J when integrated over the time period of 60 seconds. This calculation confirms that the energy dissipated can be derived directly from the power and time.

PREREQUISITES
  • Understanding of Ohm's Law
  • Knowledge of electrical power formulas (P = IV, P = I²R)
  • Basic principles of energy calculation in electrical circuits
  • Familiarity with units of measurement for power (Watts) and energy (Joules)
NEXT STEPS
  • Study the derivation of the energy formula from power and time
  • Learn about the relationship between voltage, current, and resistance in circuits
  • Explore practical applications of resistors in electrical engineering
  • Investigate thermal management techniques in electronic devices
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Students studying electrical engineering, physics enthusiasts, and anyone interested in understanding energy dissipation in resistive components.

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Homework Statement



What is the total energy dissipated as heat in a resistor of resistance R = 80.0 Ω when a current of I = 0.09 A passes through it for 1 minute?

Homework Equations




The Attempt at a Solution



From the given values I can work out the potential difference, but I'm stuck here because I don't know what formula to use with energy in it. But I know that electric power can be found from P=IV=I2R, but I don't know how this helps to find energy. Of course I know that [tex]P=\frac{dU}{dt}[/tex], but I don't see how to solve for the energy... :confused:
 
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It seems you have the answer hiding right in front of you...

If you know that the power drop across a resistor is (I^2)(R) then you can calculate that given the values.

Next if you assume that it drops all that power through heat 'U' over that 1min and you know that P=U/t then...
 

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