Rank Resistors by Energy Dissipation: 5Ω > 10Ω > 20Ω > 90Ω

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Homework Help Overview

The discussion revolves around ranking resistors based on the rate of energy dissipation, specifically comparing resistors of 5Ω, 10Ω, 20Ω, and 90Ω. Participants explore the relationships between resistance values and power dissipation in both series and parallel configurations.

Discussion Character

  • Exploratory, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the application of power formulas, considering both current and voltage across resistors in different configurations. There is an exploration of how to compare energy dissipation in resistors connected in parallel versus series.

Discussion Status

Some participants have provided calculations for equivalent resistances and discussed how these affect power dissipation. There is an ongoing exploration of the implications of different configurations, but no consensus has been reached on the final ranking of the resistors.

Contextual Notes

Participants question the assumptions regarding the configurations of the resistors and the impact of voltage sources on power absorption. There is mention of specific values and conditions that could alter the ranking, indicating that the discussion is still open-ended.

mattbeatlefreak
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Homework Statement


Rank the resistors according to to the rate at which energy is dissipated in them.

Mazur1e.ch31.p88.jpg


Homework Equations


P = I2R
P = V2/R
Iin=Iout at a node

The Attempt at a Solution


First I looked considered the 20 Ω (top) and the 10 Ω(bottom). The current in them would be the same, so then applying the equations you get that the energy dissipated in the 20 Ω(top) > 10 Ω(bot).
Next I looked at the 10, 5, and 20 Ω resistors in parallel. Resistors in parallel have the same voltage. Therefore, I concluded that the energy dissipated in the 5 Ω > 10 Ω > 20 Ω.
Again I was thinking that the voltage would be same in the two 90 Ω resistors, so I have their energy dissipated equal, 90Ω(left) = 90Ω(right).

I think I did that part right. However, I do not know how to go about comparing these three sets. I feel that it would be 5Ω > 10Ω > 20Ω > 90Ω = 90Ω > 20Ω(top) > 10Ω(bottom) since parallel circuits take more energy than a series configuration. Does this look correct? Thanks in advance for any help!
 
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find the equivalent of each parallel combination to reduce the circuit to a single mesh
the resultant of (10,5,20) will be less than 5 so it will absorb the least amount of power
(90,90)--> 45, the most amount.
______________________________
"parallel circuits take more energy than series" you said, this is right when you are talking about the same resistors
if connected (10,5,20) in series with a 5V voltage source they well absorb less power than if they are connected in parallel
 
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Passionate Eng said:
find the equivalent of each parallel combination to reduce the circuit to a single mesh
the resultant of (10,5,20) will be less than 5 so it will absorb the least amount of power
(90,90)--> 45, the most amount.

The equivalent resistance from the 10,5,20 is approximately 2.86 ohms, and for 90,90 is, as you said, 45 ohms. So you're saying that the order would then be [90=90]>20(top)>10(bottom)>[5>10>20]?
 
exactly
 
mattbeatlefreak said:
The equivalent resistance from the 10,5,20 is approximately 2.86 ohms, and for 90,90 is, as you said, 45 ohms. So you're saying that the order would then be [90=90]>20(top)>10(bottom)>[5>10>20]?
mattbeatlefreak said:
The equivalent resistance from the 10,5,20 is approximately 2.86 ohms, and for 90,90 is, as you said, 45 ohms. So you're saying that the order would then be [90=90]>20(top)>10(bottom)>[5>10>20]?
That is the correct order. The analysis you have looks a bit shy of actually showing that order, unless I missed something.

For instance, if there was a 30 Ω resistor replacing the 20 Ω resistor the order would be different.

The pair of 90 Ω resistors in parallel would dissipate more power than a 30 Ω resistor which is in series with the pair. However, combined they would dissipate less than twice the power, so that each dissipates lees than the 30 Ω resistor.
 

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