Solve Exponential Equation: 2+√2^x + 2-√2^x =4

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SUMMARY

The discussion centers on solving the exponential equation $$\left( 2+\sqrt {2}\right) ^{x}+\left( 2-\sqrt {2}\right) ^{x}=4$$. A user introduces the substitution $$C=(2+\sqrt {2})^x$$ and seeks clarification on how to derive the relationship $$\frac{1}{C}=\frac{1}{(2-\sqrt {2})^x}$$. This transformation is essential for simplifying the equation and finding the value of x.

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Chipset3600
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Hi, I'm having problems to solve this equation, pls help me:

$$\left( 2+\sqrt {2}\right) ^{x}+\left( 2-\sqrt {2}\right) ^{x}=4$$
 
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Chipset3600 said:
Hi, I'm having problems to solve this equation, pls help me:

$$\left( 2+\sqrt {2}\right) ^{x}+\left( 2-\sqrt {2}\right) ^{x}=4$$
Put $$C=(2+\sqrt {2})^x$$ Then $$\frac{1}{C}=\frac{1}{(2-\sqrt {2})^x}$$
NOW MY QUESTION IS, HOW DID I GET THIS?

Hint:
$$(2+\sqrt {2})^x (2-\sqrt {2})^x$$

Regards,
$$|\pi\rangle$$
 
Last edited:

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