MHB Solve Exponential Function: x1/2 + x-1/2 | Help & Explanation

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To simplify the expression (x1/2 + x-1/2)², it is crucial to avoid incorrectly distributing the exponent over addition, a common mistake known as the "freshman's dream." Instead, the expression should be expanded using the FOIL method, which involves multiplying the terms as (x1/2 + x-1/2)(x1/2 + x-1/2). This results in the correct simplification of the expression. The discussion highlights the importance of proper mathematical operations in solving exponential functions. Understanding these fundamentals is essential for accurate problem-solving in algebra.
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Hello! Could someone please help me answer this question, and explain how you answered it?

1. (x1/2 + x-1/2)2​Thank you!
 
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What are you asked to do? And what steps have you made towards doing that?
 
It just says to simplify it.
I multiplied away the brackets, getting x + x, which equals 2x. But this answer's wrong apparently...
 
Yes, there are several errors in your computations. The first error, seemingly, is that you distributed the exponent over addition. This NEVER WORKS! If you don't believe me, check this out: is
$$25=5^{2}=(2+3)^{2}=2^{2}+3^{2}=4+9=13?$$
Definitely not. So this thought doesn't work. It's so common it's called the "freshman's dream". You have to write out your expression and FOIL it:
$$(x^{1/2}+x^{-1/2})^{2}=(x^{1/2}+x^{-1/2})(x^{1/2}+x^{-1/2}).$$
Now do your firsts, outers, inners, and lasts. What do you get?
 
I got the right answer, thank you so much :)
 
You're welcome! Have a good one.
 
I have been insisting to my statistics students that for probabilities, the rule is the number of significant figures is the number of digits past the leading zeros or leading nines. For example to give 4 significant figures for a probability: 0.000001234 and 0.99999991234 are the correct number of decimal places. That way the complementary probability can also be given to the same significant figures ( 0.999998766 and 0.00000008766 respectively). More generally if you have a value that...

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