Solve for A using Cramer's rule with given k and K | QM problem help

  • Thread starter Thread starter Reshma
  • Start date Start date
  • Tags Tags
    Cramer's rule
Click For Summary

Homework Help Overview

This discussion revolves around a quantum mechanics problem involving the application of Cramer's rule to solve for the variable A, given the equations A - B = -1 and ikA - KB = ik, where k and K are constants and i represents the imaginary unit.

Discussion Character

  • Exploratory, Mathematical reasoning

Approaches and Questions Raised

  • The original poster attempts to apply Cramer's rule to find A and expresses confusion about the resulting expression not aligning with the expected proof that |A|² = 1. Some participants suggest that the expression for A appears correct and question the need for further simplification.

Discussion Status

The discussion is active, with participants providing guidance on how to manipulate the expression for A into a more recognizable form. There is acknowledgment of the correctness of the original application of Cramer's rule, and a suggestion is made to convert the expression into standard form.

Contextual Notes

Participants are navigating the complexities of complex numbers and their magnitudes, with an emphasis on ensuring the result meets the condition |A|² = 1. The original poster expresses a need for guidance rather than a complete solution.

Reshma
Messages
749
Reaction score
6
This is from a QM problem. A & B are the unknowns, k and K are given and [itex]i = \sqrt{-1}[/itex]. Use Cramer's rule to find A and show that |A|2 = 1.

[tex]A - B = -1[/tex]
[tex]ikA - KB = ik[/tex]

I applied Cramer's rule to determine A:

[tex]A = \frac{\left |\begin{array}{cc} -1 & -1 \\ ik & -K \end{array}\right|}{\left |\begin{array}{cc} 1 & -1 \\ ik & -K \end{array}\right|}[/tex]

So, I am left with:
[tex]A = \frac{K + ik}{-K + ik}[/tex]

I am stuck here, because this nowhere resembles the result I want to prove. Just guide me...
 
Physics news on Phys.org
Whats the problem? That looks correct, and it has magnitude 1.
 
You might want to put [tex]A = \frac{K + ik}{-K + ik}[/tex]
in "standard form" by multiplying both numerator and denominator by -K- ik.
 
Ah, how silly of me :biggrin:. Thanks, HallsofIvy! I got it.
 

Similar threads

  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
Replies
6
Views
1K
  • · Replies 22 ·
Replies
22
Views
2K
  • · Replies 16 ·
Replies
16
Views
2K
  • · Replies 6 ·
Replies
6
Views
1K
  • · Replies 16 ·
Replies
16
Views
3K
Replies
8
Views
1K
  • · Replies 1 ·
Replies
1
Views
2K