Solve for Pump Horsepower in 1-Inch Tube with No Heat Transfer

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Discussion Overview

The discussion revolves around calculating the horsepower required for a pump moving fluid through a 1-inch diameter tube, given specific parameters such as fluid density, flow rate, and pressure rise, while assuming no heat transfer. The conversation touches on thermodynamic principles and fluid dynamics.

Discussion Character

  • Homework-related
  • Technical explanation
  • Mathematical reasoning

Main Points Raised

  • One participant presents the problem statement and expresses confusion about applying the first law of thermodynamics, suggesting the need for density relations to find specific volume and enthalpy.
  • Another participant notes that the flow rate is 12 lb/s and proposes calculating the speed after the pump, assuming the speed before the pump is zero and that there is no height difference between input and output.
  • A later reply emphasizes the relationship between the rate of doing shaft work and the rate of change of enthalpy, stating that since there is no temperature change, it simplifies to ΔP times the volumetric flow rate.
  • Participants discuss unit conversions, specifically how to convert pressure change into appropriate units for calculating horsepower.
  • One participant mentions the conversion factor for horsepower, indicating a need to relate calculated units to horsepower.

Areas of Agreement / Disagreement

Participants express varying levels of understanding regarding the application of thermodynamic principles and fluid dynamics to the problem. There is no consensus on the approach to take or the specific calculations needed to arrive at the horsepower value.

Contextual Notes

Participants have not resolved the necessary assumptions for calculations, such as the treatment of velocity and pressure units, and the implications of assuming no heat transfer. The discussion remains focused on the initial setup and understanding of the problem rather than arriving at a final answer.

MonkeyMouse
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Homework Statement


This was a thermodynamics question;
A fluid is being moved by a pump though a 1inch diameter tube. The density is 100 lb/ft3 with a flow of 12 lb/s. The pressure rises 40lbf/in. Assume there is no heat transfer. Find hp of the pump to the nearest 1/4hp.

Homework Equations



I assumed that the first law of thermodynamics was needed:
0=Qcv-wcv+m[(h1-h2)+(V12-V22)+g(z1-z2)]

The Attempt at a Solution



I assumed Q=0 but was rather confused on how to even start this equation. I believe you would need to use density relations to find the specific volume and enthalpy in order to apply the 1st law of thermodynamics? Would this be better suited to be solved in terms of fluid dynamics?
 
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MonkeyMouse said:

Homework Statement


This was a thermodynamics question;
A fluid is being moved by a pump though a 1inch diameter tube. The density is 100 lb/ft3 with a flow of 12 lb/s. The pressure rises 40lbf/in. Assume there is no heat transfer. Find hp of the pump to the nearest 1/4hp.

Homework Equations



I assumed that the first law of thermodynamics was needed:
0=Qcv-wcv+m[(h1-h2)+(V12-V22)+g(z1-z2)]

The Attempt at a Solution



I assumed Q=0 but was rather confused on how to even start this equation. I believe you would need to use density relations to find the specific volume and enthalpy in order to apply the 1st law of thermodynamics? Would this be better suited to be solved in terms of fluid dynamics?

It is said that, flow is 12 lb/s
So you can calculate the speed after the pump (you have diameter of the tube too)There is nothing about the speed before the pump, so we can assume it is zero.
Nothing is said about any diference in height of input/output too.
So

(z1-z2)=0

and because

2e9c7d6144b4cd931e5adc6efdfd4abe.png


and

ba3399371b47afbbb17d58d2c272ea18.png


you can easy calculate the power
η has to be 1, because it is said, there is no heat transfer

http://en.wikipedia.org/wiki/Pump
 
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Still pretty stuck, I am unsure how to get the change in P into psf from the units had once I incorporate the velocity?
 
What is the volumetric flow rate? Neglect the temperature rise. The rate of doing shaft work is equal to the rate of change of enthalpy for the mass going through the pump. Since there is no temperature change, it is just ΔP times the volumetric flow rate.
 
So just (5760lb/ft^2)(.12ft^2/s)... how would I get hp from those units?
 
MonkeyMouse said:
So just (5760lb/ft^2)(.12ft^2/s)... how would I get hp from those units?
1HP is 550 ft-lbs/sec.
 
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