Solve for Tension: Find Magnitude of Tension in Connecting Cord

[chaotixmonjuish]

A 1.2 kg mass, m2, on a 30.1° incline is connected to a 5.4 kg mass, m1, on a horizontal surface. The surfaces and the pulley are frictionless. If F = 20.8 N, what is the magnitude of the tension in the connecting cord?

I created a FBD for both masses
M2
X: F+T-mg*sin(theta)=m2a
Y: N-mg*cos(theta)=0

M1
X: F=m1a
Y: N-mg=0

I derived this equation

F+m1a-m2g*sin(theta)=m2a

Is this equation on the right path?

 

[Astronuc]

If F is pulling m2 up the incline, then T acting on m2 will have the opposite sign, and T (between m1 and m2) will be acting on m1.

 

[chaotixmonjuish]

Well I was able to solve this, but there was a lot of dispute as to how to derive the equation.

I'm not sure what was wrong with my derviation, but the answer is 12.2 N.