Solve for the initial value of the differential equation

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SUMMARY

The discussion focuses on solving the initial value problem defined by the differential equation y + (3x - xy + 2)dy/dx = 0 with the initial condition y(1) = 1. The user attempted to separate variables by making x the dependent variable, resulting in the equation dx/dy = x(1 - 2/y) - (2/y), which was then transformed into linear standard form: dx/dy + (3/y - 1)x = -2/y. The user seeks validation on the correctness of their steps and the final answer.

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jpp46656
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Homework Statement



Solve the initial value problem: y+(3x-xy+2)dy/dx = 0 , y(1)=1

I couldn't separate with y as a dependent variable, so I made x the dependent variable and I get this: dx/dy= x(1-2/y)-(2/y),
in linear standard form: dx/dy+(3/y - 1)x = -2/y.


Homework Equations





The Attempt at a Solution



You can see that I attempted the solution. I'm just wondering if I performed the steps correctly and if the answer is correct.
 

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Oh, and the work is shown in the pictures.
 
jpp46656 said:
I'm just wondering if I performed the steps correctly and if the answer is correct.
Did you try substituting the solution back into the given equations?
 

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