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Solve for the initial value of the differential equation

  1. Jan 31, 2014 #1
    1. The problem statement, all variables and given/known data

    Solve the initial value problem: y+(3x-xy+2)dy/dx = 0 , y(1)=1

    I couldn't separate with y as a dependent variable, so I made x the dependent variable and I get this: dx/dy= x(1-2/y)-(2/y),
    in linear standard form: dx/dy+(3/y - 1)x = -2/y.


    2. Relevant equations



    3. The attempt at a solution

    You can see that I attempted the solution. I'm just wondering if I performed the steps correctly and if the answer is correct.
     

    Attached Files:

  2. jcsd
  3. Jan 31, 2014 #2
    Oh, and the work is shown in the pictures.
     
  4. Jan 31, 2014 #3

    haruspex

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    Did you try substituting the solution back into the given equations?
     
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