Webs993
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im having a problem solving this problem algebraically please help thanks
e^x - 15e^-x = 2
e^x - 15e^-x = 2
Solve for x: e^x - 15e^-x = 2 | Algebraic Solution & Step-by-Step Guide
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praharmitra
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put e^x = y. And then solve for y
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Remember the rule: [tex]a.b^{-c}=\frac{a}{b^c}[/tex]
You will have a quadratic in [tex]e^x[/tex]
You will have a quadratic in [tex]e^x[/tex]
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