Solve Force at C: Magnitude & Direction | Help Needed

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SUMMARY

The discussion focuses on calculating the magnitude and direction of the reaction force at point C in a static equilibrium scenario. The user successfully determined the upward force at point AB to be 166.7N using the formula F = ((9x150 + 19.62×350) / 50) / cos9.782. To find the reaction force at C, the user is advised to perform a summation of moments about point C, disregarding the forces at A, and then calculate the horizontal and vertical components of the reaction force at C through the summation of forces in both axes.

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Jaydee
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Homework Statement
Finding missing force on a (beam)
Relevant Equations
Basic trig
Can anyone help me solve the magnitude and direction of force at C.

I've managed to get a value for AB. Using basic trig and substituting into F= ((9x150+19.62×350) / 50) / cos9.782

Therefore producing an upward force at AB=166.7N

when it comes to force @ C.. I'm lost!
 

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The reaction force at fulcrum C should be the summation of all the forces in x and y.
The mechanism is in equilibrium, regarding forces and moments.
Without that reaction force at C, the forearm will rotate counter-clockwise about point A, and A will move towards the right some.

Do a summation of moments about point C, on which ##F_{Ay}## and ##F_{Cy}## and ##F_{Cx}## are irrelevant.
You could then calculate the values of ##F_{Cx}## and ##F_{Cy}## via summation of forces on x-axis and y-axis.

Please, see:
https://skyciv.com/docs/tutorials/beam-tutorials/how-to-calculate-reactions-at-supports/

:cool:
 
Last edited:

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