Solve Friction Work Problem: Boy Pulls Wagon 25.0kg 20.0m 60.0N 0.214

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SUMMARY

The discussion centers on calculating the work done by a boy pulling a 25.0 kg wagon with a force of 60.0 N at an angle of 40.0° over a distance of 20.0 m, with a coefficient of friction of 0.214. The formula used for work is W = FdCos(θ), which effectively incorporates the angle of the force applied. The problem is identified as "overspecified," indicating that not all provided information is necessary for the solution. The friction force is acknowledged as balancing the horizontal pull from the boy, confirming the calculations align with the physics principles involved.

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Homework Statement


A boy pulls his wagon of mass 25.0kg at a constant velocity a distance of 20.0m. the wagon's handle makes an angle of 40.0° with the ground while the boy is pulling on it with a force of 60.0N. The coefficient of friction is 0.214. how much work did the boy do on the wagon

Homework Equations



W=FdCos(theta)

The Attempt at a Solution



Not sure where to start. I am not sure where the friction fits in.
 
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As written, this is what's known as an "overspecified" problem. There is actually more information given than what is required.

Using F d cosθ, using the given 60.0 N force, will work just fine.

Alternatively you could balance the forces to find the normal and friction forces. The friction force should balance the horizontal pull from the boy ... though they turn out to be slightly different using the numbers given here (?).
 
Alright that makes scene. It worked out for me. I hate the extra stuff in problems.
 

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