Solve Hard GCD Problems: Prove d=d1d2 with d1|a and d2|b

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SUMMARY

The discussion focuses on proving that if \( d \) divides \( ab \) and \( \text{gcd}(a, b) = 1 \), then \( d \) can be expressed as \( d = d_1 d_2 \), where \( d_1 \) divides \( a \), \( d_2 \) divides \( b \), and \( \text{gcd}(d_1, d_2) = 1 \). The proof begins by defining \( d_1 \) as \( \text{gcd}(d, a) \) and suggests utilizing prime decompositions of \( a \), \( b \), and \( ab \) to facilitate the proof. This approach leverages the properties of coprime integers and their prime factors.

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lordy12
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1. If d|ab and gcd(a,b)=1, prove that d=d1d2 where d1|a and d2|b and gcd(d1,d2) = 1



Homework Equations





3. Let d1 = gcd(d,a). Thats all I know
 
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Write down prime decompositions for a, b, and ab, and see if that helps you out. :smile:
 

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