Solve Heat Capacity Question: 12kg Water, 15.4°C to 93°C

Click For Summary
SUMMARY

The discussion centers on calculating the heat required to raise the temperature of 12 kg of water from 15.4°C to 93°C. The formula used is Q = mCΔT, where m is the mass (12 kg), ΔT is the temperature change (77.6 K), and C is the specific heat capacity of water. The specific heat capacity of water is established as 4.186 J/g°C, which is essential for solving the problem accurately. Participants emphasize the importance of using the correct units and conversions in calculations.

PREREQUISITES
  • Understanding of specific heat capacity
  • Familiarity with the formula Q = mCΔT
  • Basic knowledge of unit conversions (kg to g)
  • Concept of temperature change (ΔT)
NEXT STEPS
  • Research the specific heat capacity of various substances
  • Learn about unit conversions in thermal calculations
  • Explore advanced thermodynamics concepts
  • Practice solving heat transfer problems using different materials
USEFUL FOR

Students studying thermodynamics, educators teaching heat transfer concepts, and anyone needing to calculate thermal energy changes in physical systems.

geffman1
Messages
67
Reaction score
0

Homework Statement


hey guys I've got a question.
'calculate the amount of heat necessary to raise the temperture of 12kg of water from 15.4degrees to 93 degrees.

My working= h=mCdelatT
m=12000
C?
Delta T=77.6K

just wondering how i find C? (heat capacity)

thansk for any help


Homework Equations





The Attempt at a Solution

 
Physics news on Phys.org
Tables.
 

Similar threads

  • · Replies 5 ·
Replies
5
Views
3K
  • · Replies 28 ·
Replies
28
Views
4K
  • · Replies 2 ·
Replies
2
Views
995
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 1 ·
Replies
1
Views
6K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 1 ·
Replies
1
Views
7K
Replies
1
Views
5K
Replies
5
Views
9K
  • · Replies 2 ·
Replies
2
Views
3K