- #1

shaka23h

- 38

- 0

OK I know to use the Conduction of Heat Through A material on this problem

Q = (k A Delta T) t/ L

After plugging in my values Q = [.045 J/ (s.m.C (degrees)] (1.44m ^2) (160 degrees - 38.6 degrees)(13968 sec) (hours converted to seconds) / 0.0249 m

I get my answer to be 4412945.581 J? This should be my energy value right? The Q in this case is my energy expenditure?

I plugged this answer in for the webbased solution but it was incorrect.

Thanks for ur help

Jason