Solve Heat Transfer Question: Find Rate of Heat Loss from 700m^2 Ceiling

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Homework Statement


The 700m^2 ceiling of a building has a thermal resistance of 0.2 m^2K/W. Find the rate at which heat is lost through this ceiling when the ambient temperature is -10C and the interior is 20C.



Homework Equations


Newton's law of cooling:

Q=hA(Ts - Tinfinity)

The Attempt at a Solution



Ts = 20C
Tinfinity = -10C
A = 700m^2


Anyone want to help me out with this one? Would be greatly appreciated!
 
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Newton's law of cooling is,

[tex]\frac{dQ}{dt} = A h (T_{env}-T(t) )= Ah \Delta T[/tex]

where:

Q is the thermal energy in joules
A is the surface area of the heat being transferred
h is the heat transfer coefficient
T_env is the temperature of the environment
T(t) is the temperature of the objects surface and interior

You have all these numbers given, now just plug them in!

Note: The heat transfer coefficient has SI units in watts per meter squared-kelvin, i.e. the heat transfer coefficient is the inverse of thermal insulance.