Solve Improper Integral: \int_{-3}^{1}\frac{x}{\sqrt{9-x^{2}}}

Join the discussion
Registration is free. Start your own thread to ask a follow-up.
3 replies · 2K views
darkchild
Messages
153
Reaction score
0

Homework Statement


[tex]\int_{-3}^{1}\frac{x}{\sqrt{9-x^{2}}}[/tex]

Homework Equations



Let f be continuous on the half-open interval (a, b] and suppose that
[tex]\lim_{x \to a^{+}} |f(x)| = \infty[/tex]. Then

[tex]\int_{a}^{b}f(x) dx = \lim_{ t \to a^{+}}\int_{t}^{b}f(x)<br /> dx[/tex]



The Attempt at a Solution



[tex]\int_{-3}^{1}\frac{x}{\sqrt{9-x^{2}}}<br /> <br /> = \lim_{ t \to -3^{+}}\int_{t}^{1}\frac{x}{\sqrt{9-x^{2}}}<br /> [/tex]

[tex]u = 9 - x^{2}[/tex]
[tex]du = -2x dx[/tex]

[tex]\lim_{ t \to -3^{+}}\int_{t}^{1}\frac{x}{\sqrt{9-x^{2}}}<br /> <br /> = \lim_{ t \to 0^{+}}-\frac{1}{2}\int_{t}^{8} u^{-1/2} du <br /> <br /> =\lim_{ t \to 0^{+}}-u^{1/2}|_{t}^{8}<br /> <br /> =-\sqrt{3sin(1)} + \lim_{ t \to -3^{+}}\sqrt{3sin(t)}<br /> <br /> =-1.588840129 + ?[/tex]

I get 0 for the limit, but according to Maple and my graphing calculator, that does not give the correct value for this integral. The correct value is approximately -2.8. May I please have some guidance as to what may have went wrong?
 
Physics news on Phys.org
darkchild said:
[tex]\int_{-3}^{1}\frac{x}{\sqrt{9-x^{2}}}<br /> <br /> = \lim_{ t \to -3^{+}}\int_{t}^{1}\frac{x}{\sqrt{9-x^{2}}}<br /> [/tex]

[tex]u = 9 - x^{2}[/tex]
[tex]du = -2x dx[/tex]

[tex]\lim_{ t \to -3^{+}}\int_{t}^{1}\frac{x}{\sqrt{9-x^{2}}}<br /> <br /> = \lim_{ t \to 0^{+}}-\frac{1}{2}\int_{t}^{8} u^{-1/2} du <br /> <br /> =\lim_{ t \to 0^{+}}-u^{1/2}|_{t}^{8}<br /> <br /> =-\sqrt{3sin(1)} + \lim_{ t \to -3^{+}}\sqrt{3sin(t)}<br /> <br /> =-1.588840129 + ?[/tex]

I get 0 for the limit, but according to Maple and my graphing calculator, that does not give the correct value for this integral. The correct value is approximately -2.8. May I please have some guidance as to what may have went wrong?

I don't understand that step where you introduce sine. You should just get:

[tex] \lim_{ t \to 0^{+}}-u^{1/2}|_{t}^{8}<br /> <br /> =-\lim_{t \to 0^+}(\sqrt{8} - \sqrt{t})<br /> <br /> = 0 - 2\sqrt{2}<br /> <br /> = -2\sqrt{2}<br /> <br /> \approx -2.8[/tex]
 
xeno_gear said:
I don't understand that step where you introduce sine. You should just get:

Oh, god, I made an incredibly stupid mistake...Thank you.