Solve Improper Integral: \int_{-3}^{1}\frac{x}{\sqrt{9-x^{2}}}

Click For Summary

Homework Help Overview

The problem involves evaluating the improper integral \(\int_{-3}^{1}\frac{x}{\sqrt{9-x^{2}}}\), which presents challenges due to the behavior of the integrand near the lower limit of integration.

Discussion Character

  • Exploratory, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the setup of the integral and the limits involved, with one participant attempting to apply a substitution method. There is a focus on understanding the behavior of the integral as it approaches the lower limit.

Discussion Status

The discussion includes attempts to clarify the steps taken in the evaluation of the integral. One participant expresses confusion over a specific step involving sine, while another acknowledges a mistake in their reasoning. There is an indication of productive dialogue as participants seek to understand the implications of their calculations.

Contextual Notes

Participants are navigating the complexities of improper integrals and the continuity of the function involved. There is a mention of discrepancies between calculated values and those provided by computational tools, suggesting a need for careful examination of assumptions and steps taken in the evaluation process.

darkchild
Messages
153
Reaction score
0

Homework Statement


[tex]\int_{-3}^{1}\frac{x}{\sqrt{9-x^{2}}}[/tex]

Homework Equations



Let f be continuous on the half-open interval (a, b] and suppose that
[tex]\lim_{x \to a^{+}} |f(x)| = \infty[/tex]. Then

[tex]\int_{a}^{b}f(x) dx = \lim_{ t \to a^{+}}\int_{t}^{b}f(x)<br /> dx[/tex]



The Attempt at a Solution



[tex]\int_{-3}^{1}\frac{x}{\sqrt{9-x^{2}}}<br /> <br /> = \lim_{ t \to -3^{+}}\int_{t}^{1}\frac{x}{\sqrt{9-x^{2}}}<br /> [/tex]

[tex]u = 9 - x^{2}[/tex]
[tex]du = -2x dx[/tex]

[tex]\lim_{ t \to -3^{+}}\int_{t}^{1}\frac{x}{\sqrt{9-x^{2}}}<br /> <br /> = \lim_{ t \to 0^{+}}-\frac{1}{2}\int_{t}^{8} u^{-1/2} du <br /> <br /> =\lim_{ t \to 0^{+}}-u^{1/2}|_{t}^{8}<br /> <br /> =-\sqrt{3sin(1)} + \lim_{ t \to -3^{+}}\sqrt{3sin(t)}<br /> <br /> =-1.588840129 + ?[/tex]

I get 0 for the limit, but according to Maple and my graphing calculator, that does not give the correct value for this integral. The correct value is approximately -2.8. May I please have some guidance as to what may have went wrong?
 
Physics news on Phys.org
darkchild said:
[tex]\int_{-3}^{1}\frac{x}{\sqrt{9-x^{2}}}<br /> <br /> = \lim_{ t \to -3^{+}}\int_{t}^{1}\frac{x}{\sqrt{9-x^{2}}}<br /> [/tex]

[tex]u = 9 - x^{2}[/tex]
[tex]du = -2x dx[/tex]

[tex]\lim_{ t \to -3^{+}}\int_{t}^{1}\frac{x}{\sqrt{9-x^{2}}}<br /> <br /> = \lim_{ t \to 0^{+}}-\frac{1}{2}\int_{t}^{8} u^{-1/2} du <br /> <br /> =\lim_{ t \to 0^{+}}-u^{1/2}|_{t}^{8}<br /> <br /> =-\sqrt{3sin(1)} + \lim_{ t \to -3^{+}}\sqrt{3sin(t)}<br /> <br /> =-1.588840129 + ?[/tex]

I get 0 for the limit, but according to Maple and my graphing calculator, that does not give the correct value for this integral. The correct value is approximately -2.8. May I please have some guidance as to what may have went wrong?

I don't understand that step where you introduce sine. You should just get:

[tex] \lim_{ t \to 0^{+}}-u^{1/2}|_{t}^{8}<br /> <br /> =-\lim_{t \to 0^+}(\sqrt{8} - \sqrt{t})<br /> <br /> = 0 - 2\sqrt{2}<br /> <br /> = -2\sqrt{2}<br /> <br /> \approx -2.8[/tex]
 
xeno_gear said:
I don't understand that step where you introduce sine. You should just get:

Oh, god, I made an incredibly stupid mistake...Thank you.
 
haha, it happens. no worries.
 

Similar threads

Replies
4
Views
3K
  • · Replies 105 ·
4
Replies
105
Views
11K
  • · Replies 8 ·
Replies
8
Views
2K
  • · Replies 7 ·
Replies
7
Views
2K
Replies
3
Views
2K
Replies
6
Views
3K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 6 ·
Replies
6
Views
2K
  • · Replies 11 ·
Replies
11
Views
3K
  • · Replies 23 ·
Replies
23
Views
2K