- #1

Nanu Nana

- 95

- 5

## Homework Statement

Determine the function for which y '= x ^ 2, and (2,6) is a point of the graph.

## Homework Equations

y(x)=∫ x^2 dx

## The Attempt at a Solution

I tried doing this but didn't get the right answer

y(x)=∫ x^2 dx

= x^3/3 +c

x=2 y=6

6=(2)^3 /3 +c

C= 3,33...

But according to the correctionpaper, its wrong . Answer should be x^3-3y+10 =0

How ??