Solve Jumping Toy Problem: Find Spring Constant & Power

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SUMMARY

The discussion focuses on solving the Jumping Toy Problem, where a spring compresses 1.5 cm to propel a 49g toy to a height of 45 cm. The spring constant (k) is determined using the formula k = (m * g) / Δx, where m is the mass (0.049 kg) and g is the acceleration due to gravity (9.81 m/s²). The average power during propulsion is calculated using the work-energy principle, specifically W = ½ k X², and the power formula P = W/t, where t is derived from the spring's oscillation period. The instantaneous power at 0.75 cm compression can be evaluated similarly by adjusting the extension value in the equations.

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Homework Statement


A spring is compressed 1.5 cm and propels a 49g toy to a height of 45 cm.
a. Find the spring constant
b. The average power of the spring during propulsion.
c. The instantaneous power exerted when the compression is just .75cm

Homework Equations


k=F/\Deltax
Power=Work/time


The Attempt at a Solution


i thought the spring constant ,k, would be (mass of toy x 9.81)/(.015), but this is wrong.
then work would be, force(which i don't know how to find) x distance(.45).. but I am not sure
 
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Try Using this:

Elastic potential energy stored in wire or spring (Amount of work stored)

* W = ½keffX2, where X is the extension of spring
 
Okay, but I'm still not sure how to find the spring constant, was I on the right track by using F/\Deltax, where x=.015 m
 
and force is equal to .049x9.81
 
Okay so i figured out the constant by conservation of energy.
1/2kx2=mgh, solve for k
then for power p=w/t, i find t by finding\omega=sqrt. (k/m) then using that to find T, the period.
then work= 1/2kx2, so then i just divide the w/T, would this be correct?
 

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