Solve Kinematic Problem: Man Shot from Cannon onto Net

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Thekhan
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In this particular act, a man is shot out of a cannon with an initial velocity of 10 m/s at an angle of 60 degrees onto a net at some distance away. The cannon is 6.5m above the ground, and the net is 2.5m above the ground.

How long does it take for the man to land on the net?
how far is the net from the cannon?
what is the magnitude and direction of the man's velocity when he lands on the net?

I'm sort of lost on this problem, i know I'm supposed to find the Vxi and Vyi via cos and sin but i am not sure where to go from there, please help.
 
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take the x and y components of velocity, and solve them separately with help of equations of motion.

PS: Show how you work out from next time.
 
Note that the X and Y components can be treated independantly. Just take the vertical component (Y) alone and find out the time it takes to go up and come back (ignore wind resistance). During that time, the horizontal component is constant (ignoring wind resistance). Once you find the time to land, then distance is horizontal velocity multiplied by time. When he lands on the net, the vertical component is the same as the initial vertical component (assuming no wind resistance) and horizontal is same. So this essential means that energy is not destroyed!