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Solve log(base4)X + log(base4) (X+6) <2

  1. Nov 22, 2009 #1
    1. The problem statement, all variables and given/known data
    Solve log(base4)X + log(base4) (X+6) <2


    2. Relevant equations
    log(base4)X + log(base4) (X+6) =2 comes out to x=-8 and X=2


    3. The attempt at a solution
    I can't seem to figure out what steps I should even take to answer this inequality.
     
  2. jcsd
  3. Nov 22, 2009 #2
    Re: inequality

    this property should be useful:
    [tex]log_a (b*c) = log_a b + log_a c[/tex]
    applying this to your inequality and changing 2 into [tex]log_4 16[/tex] you'll get something that can be easily transferred into inequality containing quadratic function, which you'll surely solve on your own
     
  4. Nov 22, 2009 #3

    Mark44

    Staff: Mentor

    Re: inequality

    One relevant equation here would be logaA + logaB = logaAB.
    Another is logab = c <==> b = ac.
    The equation you have here is part of your work, not really a relevant equation.
    First off, you should determine which values of x are going to be allowed as potential solutions. Then, see if the equations I added might be of some help to you.
     
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