Solving for x in 3^(log(base4)x)

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Homework Help Overview

The discussion revolves around the integration of the expression 3^(log(base4)x), exploring the transformation of logarithmic bases and the implications for integration techniques.

Discussion Character

  • Exploratory, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss changing the base of the logarithm and applying properties of exponents. Some express difficulty in manipulating the expression, while others suggest alternative forms for integration.

Discussion Status

There appears to be a mix of attempts to clarify the integration process and explore different forms of the expression. Some participants offer guidance on changing logarithmic bases and integrating exponential forms, while others reflect on their progress without reaching a consensus.

Contextual Notes

Participants mention challenges with the chain rule and the presence of x in the denominator, indicating potential constraints in their approaches. There is also a reference to the need for clarity in the integration process.

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Homework Statement



integrate 3^(log(base4)x)

Homework Equations


The Attempt at a Solution



i tried to write it in different ways. couldn't solve.
i tried to divide the whole thing by ln3 and then add some more constants to cancel out the remainings. still i could not cancel out the x in the denominator which comes from the chain rule.
 
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First, change the base of the log to base 3, using the correct formula.
Then apply the formula [tex]3^{\log_3(x)}=x[/tex].
 
thank you very much for your help. at least i succeed
 
So you have to integrate

[tex]3^{x\ln 4}[/tex]

Then you'll have to integrate

[tex]\left(e^{\ln 3}\right)^{x\ln 4}[/tex]

which should be trivial, right ?

Unless you may have to integrate

[tex]3^\log_4 x[/tex]

in which case you have to integrate

[tex]\left(e^{\ln 3}\right)^{\frac{\ln x}{\ln 4}}[/tex]

which again should be trivial.
 

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