Solve Log Law Problems Homework Statement

  • Thread starter Thread starter AbsoluteZer0
  • Start date Start date
  • Tags Tags
    Law Log
Join the discussion
Ask a follow-up here, or get your own question answered by working scientists, mathematicians and engineers — people, not an autocomplete.
Real named experts · corrections over time · the nuance an AI answer skips
8 replies · 3K views
AbsoluteZer0
Messages
124
Reaction score
1

Homework Statement

Write as a single logarithm:

Homework Equations



Logarithm Laws:

[itex]log_a(xy) = log_a(x) + log_a(y)[/itex]

[itex]log_a(\frac{x}{y}) = log_a(x) - log_a(y)[/itex]
___________

Problem Set:

[itex]log_{10}A + log_{10}B - log_{10}C[/itex]

[itex]\frac{1}{2}logX - 2log4[/itex]

[itex]2logN + 3logX[/itex]

The Attempt at a Solution



I simplified the first question to [itex]log_{10}(\frac{AB}{C})[/itex] Am I correct?

I wasn't sure about how to approach the second question. I multiplied [itex]\frac{1}{2}[/itex] by [itex]X[/itex] and [itex]2[/itex] by [itex]4[/itex] and simplified as follows:

[itex]log_{10}{\frac{1}{2}X} - log_{10}8[/itex]

to get [itex]log_{10}(\frac{0.5x}{8})[/itex]

I'm not sure if this is correct though.

If it is wrong, how would I solve it correctly?

For the third problem, I solved it to:

[itex]log_{10}[ (2n)(3x) ][/itex]

Thanks,
 
Physics news on Phys.org
AbsoluteZer0 said:
I simplified the first question to [itex]log_{10}(\frac{AB}{C})[/itex] Am I correct?

Yes..Thats right.

AbsoluteZer0 said:
I wasn't sure about how to approach the second question. I multiplied [itex]\frac{1}{2}[/itex] by [itex]X[/itex] and [itex]2[/itex] by [itex]4[/itex] and simplified as follows:

[itex]log_{10}{\frac{1}{2}X} - log_{10}8[/itex]

to get [itex]log_{10}(\frac{0.5x}{8})[/itex]

I'm not sure if this is correct though.

If it is wrong, how would I solve it correctly?

For the third problem, I solved it to:

[itex]log_{10}[ (2n)(3x) ][/itex]

Thanks,

That is not the correct way .

Use the following property of logarithms : logb(xn) = n logbx.
 
I solved the second one to:

[itex]log_{10}\frac{X^{0.5}}{16}[/itex]

Is this correct?

Thanks
 
AbsoluteZer0 said:
I solved the second one to:

[itex]log_{10}\frac{X^{0.5}}{16}[/itex]

Is this correct?

Thanks

Correct
 
And would the second one be

[itex]log_{10}(N^2X^3)[/itex]?

Thanks
 
AbsoluteZer0 said:
And would the second one be

[itex]log_{10}(N^2X^3)[/itex]?

Thanks

:thumbs:
 
  • Like
Likes   Reactions: 1 person
Thank you very much!