Solve Log Rate Law Problem | Step-by-Step Guide for Optimal Results

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Discussion Overview

The discussion revolves around solving a logarithmic rate law problem, specifically focusing on the calculations involving logarithms and their properties. The scope includes mathematical reasoning and technical explanations related to logarithmic functions.

Discussion Character

  • Mathematical reasoning, Technical explanation

Main Points Raised

  • One participant questions a calculation related to logarithms, specifically log(0.1).
  • Another participant asserts that log(0.1) equals -2.303 and prompts others to verify their calculations.
  • A participant explains that the logarithm and antilogarithm cancel each other out in certain calculations.
  • There is clarification provided regarding the natural logarithm (ln) and its base, which is e.
  • One participant confirms their understanding of the logarithmic calculations presented.
  • A participant demonstrates the calculation of ln(0.1) using properties of logarithms.

Areas of Agreement / Disagreement

Participants appear to engage in a technical discussion with some agreement on the properties of logarithms, but no consensus is reached on the overall problem or its solution.

Contextual Notes

Some calculations and assumptions regarding logarithmic properties are presented, but the discussion does not resolve all mathematical steps or potential misunderstandings.

r12214001
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Homework Statement
calculation
Relevant Equations
log problem
my question is in fig.
圖片1.png
 
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log0.1=-2.303
because that is what it is when you calculate it
did you calculate it?

you do not need to calculate it thought as the log and antilog cancel
$$\mathrm{antilog}(-1.040+\log(0.010))=\mathrm{antilog}(-1.040)\cdot\mathrm{antilog}(\log(0.100))
=\mathrm{antilog}(-1.040)\cdot(0.100)$$
 
ln means natural logarithm, base e.
 
TKS i get it
 
$$\ln{0.1}=\ln{\left(\frac{1}{10}\right)}=\ln{1}-\ln{10}=0-2.303=-2.303$$
 
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