Solve Parseval's Identity for 1+\frac{1}{9}+\frac{1}{25}+\cdot\cdot\cdot

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SUMMARY

The infinite sum 1 + 1/9 + 1/25 + ... can be solved using Parseval's Identity applied to the Fourier series of a piecewise function defined as 0 for -π/2 < x < π/2 and 1 for π/2 < x < 3π/2. The Fourier coefficients a_n are defined as -2/(nπ) for n = 1, 5, 9, 13,... and 2/(nπ) for n = 3, 7, 11, 15,..., while b_n coefficients are zero due to the even nature of the function. By evaluating the integral in Parseval's Identity, the sum converges to a specific value, confirming the relationship between the Fourier series and the infinite series.

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Mathematicians, physics students, and anyone interested in advanced calculus or Fourier analysis will benefit from this discussion, particularly those looking to deepen their understanding of Parseval's Identity and its applications in solving infinite series.

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Homework Statement


Obtain the result of the infinite sum 1+\frac{1}{9}+\frac{1}{25}+\cdot\cdot\cdot

By applying Parseval's Identity to the Fourier series expansion of
0 if -\frac{\pi}{2} &lt; x &lt; \frac{\pi}{2}
1 if \frac{\pi}{2} &lt; x &lt; \frac{3\pi}{2}

Homework Equations



2a_0^2+\sum_n{(a_n^2+b_n^2)}\leq\frac{1}{\pi}\int_{-\pi}^{\pi}\! f^2(x) \, \mathrm{d}x.

The Attempt at a Solution



I got the solution to the Fourier series, and I know it's correct.

The terms for a_n in the Fourier series expansion are \frac{-2}{n\pi} if n=1,5,9,13,..., and \frac{2}{n\pi} if n=3,7,11,15,...
The b_n terms are 0, since it is an even function about 0.

I'm just not sure how to use this information in Parseval's Identity.
 
Last edited:
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so write your sum out and see if you can relate it to the given series

in the infinite limit the inequality becomes equality, and the integral should be easy to evaluate
 

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