Solve PV Module Problem: Find I,V,P for 3 Conditions

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SUMMARY

The discussion focuses on solving for current (I), voltage (V), and power (P) in a photovoltaic (PV) module consisting of 40 cells, each rated at 0.5 volts, connected in series to a 5-ohm load. Key conditions analyzed include full sunlight, one cell in shade, and two cells in shade. In full sunlight, the voltage is confirmed at 20 volts, while shading one cell reduces it to 19.5 volts. The shaded cell behaves as a resistor with a resistance of 5 ohms due to its semiconductor properties, which is critical for understanding the overall resistance in the circuit.

PREREQUISITES
  • Understanding of photovoltaic (PV) module operation
  • Basic knowledge of electrical resistance and Ohm's Law
  • Familiarity with series circuits and load calculations
  • Concept of bypass diodes in PV systems
NEXT STEPS
  • Study the behavior of PV modules under varying light conditions
  • Learn about the impact of shading on solar cell performance
  • Research the role of bypass diodes in protecting PV modules
  • Explore advanced calculations for power output in solar energy systems
USEFUL FOR

Solar energy engineers, electrical engineers, and students studying photovoltaic systems will benefit from this discussion, particularly those interested in the effects of shading on solar module performance and circuit analysis.

Jason03
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Im working on a problem that involves a PV module consisting of 40 cells each at .5 volts. The problem models the module as having all 40 cells in series. The PV module is connected to a 5 ohm load. The problem also says to assume that the same current and voltage flows through the PV module and load. So solve for I, V, and P.

I just need to find the current, power, and voltage for 3 conditions.

a) when in full sunlight

b) when 1 cell is in shade

c) when 2 cells are in shade.


my question is:

I know the voltage to be 20 volts in full sunlight and 19.5 volts when 1 cell is in shade...so when 1 cell is in shade I noticed the book saying that one .5 volt cell will now act as a 5 ohm reisistor...is this true...and why?

and if that is the case for 1 cell in the shade would I have a total of 10 ohms resistance to calculate the current flowing?
 
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any ideas?...I can understand a cell not functioning acting as a resistor...but why 5 ohms?
 
Jason03 said:
any ideas?...I can understand a cell not functioning acting as a resistor...but why 5 ohms?

I would guess it is because that's what someone measured when they shaded an individual cell. Silicon is a semiconductor, so with no light falling on the cell, it turns into a resistor. That resistance will depend on the physical dimensions of the cell.
 
its true , for this case the PV module must protect it by bypass diode
 

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