Solve Quadratic Equations: Find Coordinates of Turning Point

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To find the coordinates of the turning point for the quadratic equation y=4x^2-8x-5, one should start by understanding the definition of a turning point, which is the vertex of the parabola. The turning point can be found by either setting the derivative equal to zero or completing the square. Completing the square is suggested as a straightforward method to determine the vertex. The discussion highlights that the turning point is where the graph changes direction, confirming it is the vertex of the parabola. This approach provides clarity on how to solve for the turning point effectively.
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y=4x^2-8x-5 Find the coordinates of the turning point of the curve. Where do I even start?
 
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With the definition of turning point.
 
I don't know that.
 
Well, then, that's where you need to start. What does your book have to say, or your notes?

(Incidentally, what level math is this?)
 
My book doesn't say anything about the definition of a turning point. I'm in grade 9.
 
If you mean the minimi/maximi-point of the curve, you can set the derivate equal to zero and solve. Wait a minute, it must be an another way... Try to completting the square on the function...
 
Where did you see the problem?


If I had to guess what it meant, I would say the point where the graph of the polynomial stops going downwards and starts going upwards. Since it's a parabola, that would be its vertex.
 
Try to completting the square on the function
Since it's a parabola, that would be its vertex.
Oh Yes! Now that you guys mention that, I know what to do now :rolleyes: Thanks!
 
Last edited:

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