Solve R1 in Rt = R3 + [ ( 1/R1 + 1/R2 ) ^-1 ] for Parallel Circuits

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SUMMARY

The discussion focuses on rearranging the formula for calculating total resistance in parallel circuits, specifically solving for R1 in the equation Rt = R3 + [ ( 1/R1 + 1/R2 ) ^-1 ]. The user seeks assistance in eliminating the inverse to isolate R1. The solution involves manipulating the equation to express R1 in terms of Rt, R2, and R3, ultimately leading to the equation 1/(Rt - R3) = 1/R1 + 1/R2.

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  • Understanding of Ohm's Law and basic circuit theory
  • Familiarity with algebraic manipulation of equations
  • Knowledge of series and parallel circuit configurations
  • Ability to work with inverse operations in mathematics
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  • Practice solving for unknowns in circuit equations
  • Explore the concept of equivalent resistance in parallel circuits
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Homework Statement



Rearrange formula for series and parallel circuit combination.
Make R1 the subject of the formula : Rt = R3 + [ ( 1/R1 + 1/R2 ) ^-1 ]

Homework Equations



Rt = R3 + [ ( 1/R1 + 1/R2 ) ^-1 ]

The Attempt at a Solution



I am unsure as to how to get rid of the inverse? please help.
 
Physics news on Phys.org
Rt = R3 + ( 1/R1 + 1/R2 )-1

Rt - R3 = ( 1/R1 + 1/R2 )-1

1/(Rt - R3) = 1/R1 + 1/R2

Continue...
 

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