Solve Resistance Question w/Kirchhoff's Laws & Ohm's Law

  • Thread starter Thread starter imagemania
  • Start date Start date
  • Tags Tags
    Resistance
Click For Summary

Homework Help Overview

The discussion revolves around a resistance problem involving Kirchhoff's Laws and Ohm's Law, specifically focusing on calculating resistances in a circuit with given power and current values.

Discussion Character

  • Mixed

Approaches and Questions Raised

  • Participants explore methods to calculate the resistance values, particularly R2, using given power and current information. Questions arise regarding the necessity of deducing current through specific resistors and the implications of the problem's wording.

Discussion Status

Some participants have offered guidance on calculating voltage across resistors and finding equivalent resistance. There is an ongoing exploration of different methods to approach the problem, with no explicit consensus on the simplest solution.

Contextual Notes

Participants note constraints such as missing information about the power through R2 and the current values, which complicate the deduction process. The problem's structure suggests certain assumptions that are being questioned.

imagemania
Messages
24
Reaction score
0

Homework Statement



http://img97.imageshack.us/f/scn0003.jpg/

Homework Equations



Kirchhoff's first, second law, ohm's law

The Attempt at a Solution


I’m ok on all the questions, just I am stuck on part a. I can work out R1 from P=I^2R and get R = 5.00 ohms. But, R2? I can't see how to deduce it without working out the current that goes through the 10ohms resistor, and deducing the voltage through the 5ohm. But the way the question is laid indicates you need not do that...

Any help would be great.
 
Physics news on Phys.org
Hi imagemania, welcome to PF.
Power W = V*I
So voltage across the parallel combination of resistance is 10 V.
Now you can find the remaining things.
 
I see that bit now, but once you've done that, there is still an issue with the current. We're not told that the power through R2 is 20W, and we're not told the current. If we take kirchhoffs second law about a loop that misses out R2 then
0 = 10ohms x I - 5ohms x 2A
I = 1A (through 10 ohm).

So through R2 it would be I = 3.5-(2+1) = 0.5A

R2 = 10/0.5 = 20ohm.

Is there another way that this is suppose to be deduced, as if you look at part b, c it asks for the steps I've taken above, which inclines there's an easier method. ..

thanks
 
I don't think so. Now three resistances are in parallel. Find equivalent resistance. Total Current is given. Find emf.
 

Similar threads

  • · Replies 18 ·
Replies
18
Views
3K
  • · Replies 7 ·
Replies
7
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
Replies
5
Views
5K
Replies
4
Views
1K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 10 ·
Replies
10
Views
2K
Replies
5
Views
2K
  • · Replies 6 ·
Replies
6
Views
2K