Solve the First Order Linear D.E. with the initial value

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SUMMARY

The discussion focuses on solving the first-order linear differential equation dy/dt = y(9-y) with the initial condition y(0) = 2. The solution process involves separating variables and using partial fraction decomposition to integrate. The user arrives at the equation y/(9-y) = (2e^(9t))/7 but is unsure how to proceed from this point. The discussion emphasizes the importance of manipulating the equation to isolate y and find the explicit solution.

PREREQUISITES
  • Understanding of first-order linear differential equations
  • Knowledge of separation of variables technique
  • Familiarity with partial fraction decomposition
  • Basic integration skills, particularly with logarithmic functions
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  • Review methods for isolating variables in differential equations
  • Study techniques for solving first-order linear differential equations
  • Learn about the application of initial conditions in differential equations
  • Explore advanced integration techniques, including logarithmic identities
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Painguy
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Homework Statement



dy/dt=y(9-y)

y(0)=2

Homework Equations





The Attempt at a Solution



dy/(y(9-y)) = dt
∫dy/(y(9-y)) = ∫dt

partial fraction decomposition
1=A/y + B/(9-y)
1=9A-Ay +By
1/9=A
0=1/9 +B
B=-1/9

1/9∫1/y -1/9∫1/(9-y)=t+C
1/9ln|y| -1/9(ln|9-y|)
1/9(ln|y/(9-y)|)=t+C
y/(9-y) =Ke^(9t)
2/7=K

y/(9-y) =(2e^(9t))/7

I'm stuck right here. It's a little embarrassing, but I forgot how to find the solution here.
 
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You're close. Start by multiplying both sides by (9-y), distribute, add a certain term to both sides, factor out a y, etc.
 

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