alejandrito29
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i need to solve the follow diferential equation:
(\frac{du}{dy})^2=A+Be^{2u}+C \sqrt{D+Ee^{4u}}
where A,B,C,D,E are nonzero.
(\frac{du}{dy})^2=A+Be^{2u}+C \sqrt{D+Ee^{4u}}
where A,B,C,D,E are nonzero.