The problem involves a uniform steel beam suspended from one end, swinging back and forth with a specified period. Participants are tasked with determining the length of the beam based on its oscillation period.
The discussion is ongoing, with participants exploring the differences between a simple pendulum and a physical pendulum. There is recognition that the moment of inertia of the beam must be considered, indicating a productive direction in the conversation.
Participants note that the original formula used may not be appropriate due to the uniform mass distribution of the beam, highlighting the need for a different approach or formula specific to this scenario.
The period equation you have written is for a simple pendulum with a point mass at the end. You cannot use it for this case, since the mass is uniformly distributed along the beam. You must find or derive the correct formula for this case.PhyzicsOfHockey said:Homework Statement
On the construction site for a new skyscraper, a uniform beam of steel is suspended from one end. If the beam swings back and forth with a period of 1.10 s, what is its length?
Homework Equations
T=2*pi*sqroor (L/g)
The Attempt at a Solution
(1.1/(2*3.14))^2*9.81=L
L=.3007m
This is wrong however and I don't understand why.