Solve Tough Thermo Problem: Find Final Pressure of Helium

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Discussion Overview

The discussion revolves around a thermodynamics problem involving gaseous helium in a rigid container, where participants seek to determine the final pressure after work is done on the gas in an adiabatic process. The scope includes theoretical reasoning and mathematical modeling related to energy balance and the ideal gas law.

Discussion Character

  • Homework-related
  • Technical explanation
  • Debate/contested

Main Points Raised

  • One participant outlines the initial conditions and the work done on the gas, expressing uncertainty about how to proceed without additional information such as mass or number of moles.
  • Another participant questions the absence of mass and suggests that without it, predicting temperature and final pressure is impossible.
  • Some participants propose using the ideal gas law (PV = nRT) to relate pressure, volume, and temperature, noting that Cv is specified in terms of moles.
  • One participant suggests assuming an initial temperature of room temperature (~293K) to make progress on the problem.
  • Another participant believes it may be solvable by assuming the number of moles is n and exploring how variables might cancel out in the equations.
  • There are multiple suggestions for approaches, but no consensus on a definitive method to solve the problem without additional data.

Areas of Agreement / Disagreement

Participants generally agree that the problem lacks sufficient information to determine the final pressure definitively. There are competing views on whether assumptions can be made to progress towards a solution.

Contextual Notes

The discussion highlights limitations due to missing data such as mass or initial temperature, which are critical for applying the ideal gas law and energy balance equations effectively.

ashy
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Homework Statement


Gaseous helium is contained in a rigid container with a volume of V=0.5 m3, and is initially at a pressure of 500 kPa. Agitation by a stirrer transfers 250 kJ of work to the gas in an adiabatic process. Cv for the gas is constant and equal to 12.46 kJ/kmol*K. What is the final pressure of the gas?
So
At state 1: V=0.5 m3, P=500 kPa,
Process 1->2: W=-250kJ
At state 2: V=0.5 m3, P=?

cv=12.46kJ/kmol*K

Homework Equations


Energy balance for the process:
Q-W=deltaU+deltaKE+deltaPE
Q=deltaPE=deltaKE=0 so
-W=deltaU, W=-250kJ so
250kJ=deltaU.

The Attempt at a Solution


This is what I have:
250kJ=deltaU=n*deltau where u=U/n and n is the number of moles of helium.
cv=du/dT so
deltau=cv*deltaT and
250 kJ=n*cv*deltaT

I don't really know where to go with this problem to find anything to do with the pressure, the equation seems underdetermined. Help?[/B]
 
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Has mass been given? Or is the given volume specific as in m3/kg?
 
No, no mass is given and the the volume given is not specific, it is just the volume of the tank.
 
What about the number of moles? It's impossible to predict the temperatures without the mass or moles therefore you won't be able to predict the final pressure.
 
no, the data given is the only available data. this is why I thought it was underdetermined. Can it even be done?
 
You may want to throw the ideal gas law, PV = nRT, into your set of Relevant Equations. Note that ##C_v## is specified in terms of moles, and n in the ideal gas law is moles. Set up a ratio and ponder on what you know about the various variables:

$$\frac{P V}{P_o V_o} = \frac{n R T }{n R T_o}$$
 
This problem is unsolvable unless either the mass, no. of moles or initial temperature are given.

You could proceed assuming initial temperature = room temperature ~ 293K.
 
I think it may be doable. Just assume that the number of moles is n and see where things go using the ideal gas law and Cv to find the change in temperature given the change in heat. I think that the n will cancel out along the way.
 
gneill said:
I think it may be doable. Just assume that the number of moles is n and see where things go using the ideal gas law and Cv to find the change in temperature given the change in heat. I think that the n will cancel out along the way.

Send me a PM on how?
rude man
 
  • #10
gneill is right. It is solvable.
 
Last edited:
  • #11
rude man said:
Send me a PM on how?
Done. Check your mail (inbox).
 
  • #12
@ashy : Did you resolve your difficulty?
 

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