- #1

rum2563

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## Homework Statement

A swimming pool is 24 m long by 8 m wide, 1 m deep at the shallow end and 3 m deep at the deep end, the bottom being an inclined plane. If water is pumped into the empty pool at a rate of 2m^3/min, then how fast is the water level rising at the moment when the water is 1 m deep at the end of the pool.

## Homework Equations

dh/dt = 1/As x dV/dt

As: area of exposed surface

## The Attempt at a Solution

Basically I used ratios to get the length of the pool when the height is 1 m deep.

1/3 = x/24

So x = 8 m.

Then As = 8*8 = 64 m^2

dh/dt = 2/64

= 1/32 m/min

I am not sure what I am doing wrong. I have my diagram attached. Please tell me what I am doing wrong. Also, if you have the answer please tell me because I need this urgently. I can use the answer and then work it back to get everything right.

Thanks.